Which out of the 2 choices is correct ?

Answer:sinB is correctStep-by-step explanation:Calculating each of cos/ sin for ∠BcosB = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{6}{3\sqrt{5} }[/tex] = [tex]\frac{2}{\sqrt{5} }[/tex] and[tex]\frac{2}{\sqrt{5} }[/tex] × [tex]\frac{\sqrt{5} }{\sqrt{5} }[/tex] = [tex]\frac{2\sqrt{5} }{5}[/tex] ≠ [tex]\frac{\sqrt{5} }{5}[/tex]--------------------------------------------------------------------------------sinB = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{3}{3\sqrt{5} }[/tex] = [tex]\frac{1}{\sqrt{5} }[/tex] and[tex]\frac{1}{\sqrt{5} }[/tex] × [tex]\frac{\sqrt{5} }{\sqrt{5} }[/tex] = [tex]\frac{\sqrt{5} }{5}[/tex]