A triangle has a perimeter of 10a + 3b +12 and has sides of length 3a+8 and 5+b, what is the length of the third side?
Accepted Solution
A:
Answer:The third side of the triangle is (7a + 2b -1).Step-by-step explanation:The length of the first side = (3a +8)The length of the second side = (5 +b)Let us assume the third side = mThe perimeter of the triangle = SUM OF ALL 3 SIDES⇒ (10a + 3b +12) = (3a +8) + (5 +b) + mor, (10a + 3b +12) = 3a + b + 13 + mor, m = (10a + 3b +12) -(3a + b + 13) = 10 a + 3b + 12 - 3a - b - 13 = 7a + 2b -1 = ( 10 - 3a) + (3b -b) + 12 -13or, m = (7a + 2b -1)Hence, the third side of the triangle is (7a + 2b -1).